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  1. ,

    You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.

  2. ,

    Can occur when you try to convert a String to a numeric value but the String is not well formatted for the conversion.

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via monkey-x.com by Unknown author, 2 years ago
via Stack Overflow by gamerguy0102
, 2 years ago
via Stack Overflow by lantonis
, 2 years ago
java.lang.NumberFormatException: Invalid int: ""	at java.lang.Integer.invalidInt(Integer.java:138)	at java.lang.Integer.parseInt(Integer.java:358)	at java.lang.Integer.parseInt(Integer.java:334)	at android.net.Uri$AbstractHierarchicalUri.parsePort(Uri.java:1127)	at android.net.Uri$AbstractHierarchicalUri.getPort(Uri.java:1106)	at ti.modules.titanium.network.TiHTTPClient.open(TiHTTPClient.java:776)	at ti.modules.titanium.network.HTTPClientProxy.open(HTTPClientProxy.java:147)	at org.appcelerator.kroll.runtime.v8.V8Object.nativeCallProperty(Native Method)	at org.appcelerator.kroll.runtime.v8.V8Object.callProperty(V8Object.java:73)	at org.appcelerator.kroll.KrollProxy.handleMessage(KrollProxy.java:1155)	at android.os.Handler.dispatchMessage(Handler.java:98)	at android.os.Looper.loop(Looper.java:148)	at org.appcelerator.kroll.KrollRuntime$KrollRuntimeThread.run(KrollRuntime.java:118)