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Samebug tips

  1. ,

    You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.

  2. ,

    Can occur when you try to convert a String to a numeric value but the String is not well formatted for the conversion.

Solutions on the web

via QuickFIX/J JIRA by Colin Crist, 1 year ago
via QuickFIX/J JIRA by Colin Crist, 2 years ago
via Stack Overflow by Ali Elsaadi
, 1 year ago
java.lang.NumberFormatException: For input string: "abc"	at java.lang.NumberFormatException.forInputString(	at java.lang.Integer.parseInt(	at java.lang.Integer.parseInt(	at quickfix.Message.parseGroup(	at quickfix.Message.parseBody(	at quickfix.Message.parse(	at quickfix.MessageUtils.parse(	at quickfix.mina.AbstractIoHandler.messageReceived(	at$TailFilter.messageReceived(	at	at$1100(	at$EntryImpl$1.messageReceived(	at	at org.apache.mina.filter.codec.ProtocolCodecFilter.messageReceived(	at	at$1100(	at$EntryImpl$1.messageReceived(	at$HeadFilter.messageReceived(	at	at	at	at org.apache.mina.transport.socket.nio.SocketIoProcessor.process(	at org.apache.mina.transport.socket.nio.SocketIoProcessor.access$500(	at org.apache.mina.transport.socket.nio.SocketIoProcessor$	at	at