java.lang.NumberFormatException: For input string: "4.0"

Searched on Google with the first line of a JAVA stack trace?

We can recommend more relevant solutions and speed up debugging when you paste your entire stack trace with the exception message. Try a sample exception.

Recommended solutions based on your search

Samebug tips


You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.


Java does not handle IPv6 nameservers before 1.8.0_60. Upgrade to the latest JVM.

Solutions on the web

via Stack Overflow by Unknown author, 2 years ago
via Coderanch by A. Wolf, 1 year ago
For input string: "4141"
via GitHub by Pandanoro
, 11 months ago
For input string: "555150788003240"
via Eclipse Bugzilla by sbalusani, 1 year ago
java.lang.NumberFormatException: For input string: "4.0"
at java.lang.NumberFormatException.forInputString(
at java.lang.Integer.parseInt(
at java.lang.Integer.parseInt(
at org.archive.crawler.datamodel.Robotstxt.(
at org.archive.crawler.datamodel.RobotsExclusionPolicy.policyFor(
at org.archive.crawler.datamodel.CrawlServer.updateRobots(
at org.archive.crawler.postprocessor.CrawlStateUpdater.innerProcess(
at org.archive.crawler.framework.Processor.process(
at org.archive.crawler.framework.ToeThread.processCrawlUri(

Users with the same issue

Samebug visitor profile picture
Unknown user
Once, 2 days ago
Samebug visitor profile picture
Unknown user
Once, 6 days ago
Once, 1 month ago
Once, 3 months ago
Samebug visitor profile picture
Unknown user
Once, 4 months ago

Write tip

Know the solutions? Share your knowledge to help other developers to debug faster.