java.lang.NumberFormatException: For input string: "4.0"

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You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.

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Solutions on the web

via Stack Overflow by Unknown author, 2 years ago
via Coderanch by A. Wolf, 1 year ago
For input string: "4141"
via GitHub by Pandanoro
, 11 months ago
For input string: "555150788003240"
via Eclipse Bugzilla by sbalusani, 1 year ago
java.lang.NumberFormatException: For input string: "4.0"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
at java.lang.Integer.parseInt(Integer.java:456)
at java.lang.Integer.parseInt(Integer.java:497)
at org.archive.crawler.datamodel.Robotstxt.(Robotstxt.java:115)
at org.archive.crawler.datamodel.RobotsExclusionPolicy.policyFor(RobotsExclusionPolicy.java:96)
at org.archive.crawler.datamodel.CrawlServer.updateRobots(CrawlServer.java:183)
at org.archive.crawler.postprocessor.CrawlStateUpdater.innerProcess(CrawlStateUpdater.java:78)
at org.archive.crawler.framework.Processor.process(Processor.java:112)
at org.archive.crawler.framework.ToeThread.processCrawlUri(ToeThread.java:302)
at org.archive.crawler.framework.ToeThread.run(ToeThread.java:151)

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