Searched on Google with the first line of a JAVA stack trace?

We can recommend more relevant solutions and speed up debugging when you paste your entire stack trace with the exception message. Try a sample exception.

Recommended solutions based on your search

Samebug tips

  1. ,

    You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.

  2. ,

    Can occur when you try to convert a String to a numeric value but the String is not well formatted for the conversion.

Solutions on the web

via GitHub by matthewrj
, 1 year ago
For input string: "20 14074,9804,9804,0.0"
via Google Groups by, 2 years ago
For input string: "true"
via Coderanch by Vladimir Razov, 1 year ago
via Eclipse Bugzilla by curious.corn, 1 year ago
For input string: "*"
via Netbeans Bugzilla by mgraybush, 1 year ago
For input string: "${default"
java.lang.NumberFormatException: For input string: "20
14074,9804,9804,0.0"	at java.lang.NumberFormatException.forInputString(	at java.lang.Integer.parseInt(	at java.lang.Integer.parseInt(	at scala.collection.immutable.StringLike$class.toInt(StringLike.scala:272)	at scala.collection.immutable.StringOps.toInt(StringOps.scala:29)	at com.redis.serialization.Parse$Implicits$$anonfun$3.apply(Serialization.scala:38)	at com.redis.serialization.Parse$Implicits$$anonfun$3.apply(Serialization.scala:38)	at com.redis.serialization.Parse.apply(Serialization.scala:54)