java.lang.StringIndexOutOfBoundsException: String index out of range: 3

Apereo Issues | Dave Steiner | 4 years ago
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    Where did I go wrong with this cipher program?

    Stack Overflow | 3 years ago | Predator44
    java.lang.StringIndexOutOfBoundsException: String index out of range: 3
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    recursive method for finding all decodings of a string of numbers

    Stack Overflow | 2 years ago | user3137376
    java.lang.StringIndexOutOfBoundsException: String index out of range: 3
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    array of words then nested for loop to check the chars

    Stack Overflow | 3 years ago | Bob
    java.lang.StringIndexOutOfBoundsException: String index out of range: 3

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Root Cause Analysis

  1. java.lang.StringIndexOutOfBoundsException

    String index out of range: 3

    at java.lang.String.charAt()
  2. Java RT
    String.charAt
    1. java.lang.String.charAt(String.java:686)
    1 frame
  3. org.openregistry.core
    JpaPhoneImpl.toString
    1. org.openregistry.core.domain.jpa.JpaPhoneImpl.toString(JpaPhoneImpl.java:184)
    1 frame
  4. edu.rutgers.openregistry
    RealTimeOutputToLdap.create
    1. edu.rutgers.openregistry.integration.ldap.RealTimeOutputToLdap.mapToContext(RealTimeOutputToLdap.java:222)
    2. edu.rutgers.openregistry.integration.ldap.RealTimeOutputToLdap.create(RealTimeOutputToLdap.java:71)
    2 frames