java.lang.NumberFormatException

For input string: "20.0.1"

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Solutions on the web5367

  • For input string: "20.0.1"
  • For input string: "20.0.1"
  • via Stack Overflow by neveu
    , 1 year ago
    For input string: "20.0.1"
  • Stack trace

    • java.lang.NumberFormatException: For input string: "20.0.1" at java.lang.NumberFormatException.forInputString(Unknown Source) at java.lang.Integer.parseInt(Unknown Source) at java.lang.Integer.parseInt(Unknown Source) at hudson.plugins.android_emulator.util.Utils$2.call(Utils.java:187) at hudson.plugins.android_emulator.util.Utils$2.call(Utils.java:156) at hudson.remoting.LocalChannel.call(LocalChannel.java:45) at hudson.plugins.android_emulator.util.Utils.getAndroidSdk(Utils.java:197) at hudson.plugins.android_emulator.AndroidEmulator.setUp(AndroidEmulator.java:225) at hudson.model.Build$RunnerImpl.doRun(Build.java:133) at hudson.model.AbstractBuild$AbstractRunner.run(AbstractBuild.java:475) at hudson.model.Run.run(Run.java:1421) at hudson.model.FreeStyleBuild.run(FreeStyleBuild.java:46) at hudson.model.ResourceController.execute(ResourceController.java:88) at hudson.model.Executor.run(Executor.java:238)

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