java.lang.NumberFormatException

For input string: "0038"

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Solutions on the web5366

  • For input string: "0038"
  • via Stack Overflow by Shantanu
    , 1 year ago
    For input string: "string"
  • Stack trace

    • java.lang.NumberFormatException: For input string: "0038" at java.lang.NumberFormatException.forInputString(Unknown Source) at java.lang.Integer.parseInt(Unknown Source) at java.lang.Integer.valueOf(Unknown Source) at java.lang.Integer.decode(Unknown Source) at dizionario_package.HashTable.HashFunction(HashTable.java:22) at dizionario_package.HashTable.HashInsert(HashTable.java:29) at dizionario_package.RecordReader.CreateHTFromFile(RecordReader.java:24) at dizionario_package.proviamo.main(proviamo.java:8)

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