java.lang.NumberFormatException: For input string: "0038"

codegur.com | 7 months ago
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    Root Cause Analysis

    1. java.lang.NumberFormatException

      For input string: "0038"

      at java.lang.NumberFormatException.forInputString()
    2. Java RT
      Integer.decode
      1. java.lang.NumberFormatException.forInputString(Unknown Source)
      2. java.lang.Integer.parseInt(Unknown Source)
      3. java.lang.Integer.valueOf(Unknown Source)
      4. java.lang.Integer.decode(Unknown Source)
      4 frames
    3. dizionario_package
      proviamo.main
      1. dizionario_package.HashTable.HashFunction(HashTable.java:22)
      2. dizionario_package.HashTable.HashInsert(HashTable.java:29)
      3. dizionario_package.RecordReader.CreateHTFromFile(RecordReader.java:24)
      4. dizionario_package.proviamo.main(proviamo.java:8)
      4 frames