java.lang.NumberFormatException: For input string: "0038"

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Solutions on the web

via Stack Overflow by user3004162
, 1 year ago
via GitHub by KenC57
, 1 year ago
For input string: "FL"
via GitHub by sho-suzuki
, 4 months ago
For input string: ""
via by Unknown author, 1 year ago
via by Unknown author, 2 years ago
java.lang.NumberFormatException: For input string: "0038"
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at java.lang.Integer.valueOf(Unknown Source)
at java.lang.Integer.decode(Unknown Source)
at dizionario_package.HashTable.HashFunction(
at dizionario_package.HashTable.HashInsert(
at dizionario_package.RecordReader.CreateHTFromFile(
at dizionario_package.proviamo.main(

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