Searched on Google with the first line of a JAVA stack trace?

We can recommend more relevant solutions and speed up debugging when you paste your entire stack trace with the exception message. Try a sample exception.

Recommended solutions based on your search

Solutions on the web

via Oracle Community by 589725, 1 year ago
JMSRemoteServer: unable to authenticate user "admin".
via Oracle Community by 107137, 1 year ago
JMSServer[aplora2:12602]: failed to authenticate "myuser/mypassword", no such user.
javax.jms.JMSSecurityException: JMSRemoteServer: unable to authenticate user "admin".	at com.evermind.server.jms.JMSUtils.make(JMSUtils.java:1072)	at com.evermind.server.jms.JMSUtils.toJMSSecurityException(JMSUtils.java:1128)	at com.evermind.server.jms.JMSRemoteServer.readLogin(JMSRemoteServer.java:711)	at com.evermind.server.jms.TCPJMSRemoteServer.initializeConnection(TCPJMSRemoteServer.java:137)	at com.evermind.server.jms.TCPJMSRemoteServer.initializeConnection(TCPJMSRemoteServer.java:110)	at com.evermind.server.jms.TCPJMSRemoteServer.(TCPJMSRemoteServer.java:68)	at com.evermind.server.jms.EvermindConnection.(EvermindConnection.java:122)	at com.evermind.server.jms.EvermindTopicConnection.(EvermindTopicConnection.java:68)	at com.evermind.server.jms.EvermindTopicConnectionFactory.unprivileged_createTopicConnection(EvermindTopicConnectionFactory.java:96)	at com.evermind.server.jms.EvermindTopicConnectionFactory.access$000(EvermindTopicConnectionFactory.java:41)	at com.evermind.server.jms.EvermindTopicConnectionFactory$1.execute(EvermindTopicConnectionFactory.java:78)	at com.evermind.server.jms.InContainerProxy.doSecureOp(InContainerProxy.java:157)	at com.evermind.server.jms.EvermindTopicConnectionFactory.createTopicConnection(EvermindTopicConnectionFactory.java:75)