Searched on Google with the first line of a JAVA stack trace?

We can recommend more relevant solutions and speed up debugging when you paste your entire stack trace with the exception message. Try a sample exception.

Recommended solutions based on your search

Samebug tips

  1. ,
    Expert tip

    Thrown to indicate that an index of some sort (such as to an array, to a string, or to a vector) is out of range. Applications can subclass this class to indicate similar exceptions.

  2. ,

    Thrown if trying to access an index which is out of bounds on objects like String, Array, or Vector. Any negative integer less than or equal to -1 and positive integer greater than or equal to the size of the object is an index which would be out of bounds

Solutions on the web

via by Unknown author, 1 year ago
via flexjson by *anonymous
, 1 year ago
via servicemix-users by Gnanaguru S, 1 year ago
via servicemix-users by Gnanaguru S, 1 year ago
via Oracle Community by 807603, 1 week ago
via Stack Overflow by user1278696
, 2 years ago
Index: 0, Size: 0
java.lang.IndexOutOfBoundsException: Index: 0, Size: 0	at java.util.ArrayList.RangeCheck(	at java.util.ArrayList.get(	at flexjson.ObjectBinder.bind(	at flexjson.ObjectBinder.bindIntoMap(	at flexjson.factories.MapObjectFactory.instantiate(	at flexjson.ObjectBinder.bind(	at flexjson.ObjectBinder.bind(	at flexjson.JSONDeserializer.deserialize(