Searched on Google with the first line of a JAVA stack trace?

We can recommend more relevant solutions and speed up debugging when you paste your entire stack trace with the exception message. Try a sample exception.

Recommended solutions based on your search

Samebug tips

  1. ,

    Use the relative path when providing the location of the file. Place the file in the project folder and access it according to the hierarchy. If you want to access a file outside the project folder, provide the absolute path.

Solutions on the web

via Oracle Community by 666705, 1 year ago
/javax/jdo/jdo.dtd (No such file or directory) [jdoc]
via Apache's JIRA Issue Tracker by Gary Gregory, 2 years ago
vfs-test/hello.txt (No such file or directory)
via freemind by christianfoltin
, 2 years ago
dictionaries.txt (No such file or directory)
via Google Groups by mortirolo, 8 months ago
/ (No such file or directory)
via GitHub by MikeSWelch
, 1 year ago
/home/mikeswelch/deeplearntest/dl4j-0.4-examples/src/main/resources/DataExamples/CSVPlotData.csv (No such file or directory)
via by Unknown author, 2 years ago (No such file or directory) /javax/jdo/jdo.dtd (No such file or directory)
[jdoc]	at Method)	at	at	at	at	at	at org.apache.xerces.impl.XMLEntityManager.startEntity(	at org.apache.xerces.impl.XMLEntityManager.startDTDEntity(	at org.apache.xerces.impl.XMLDTDScannerImpl.setInputSource(	at org.apache.xerces.impl.XMLDocumentScannerImpl$DTDDispatcher.dispatch(	at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl.scanDocument(	at org.apache.xerces.parsers.StandardParserConfiguration.parse(	at org.apache.xerces.parsers.StandardParserConfiguration.parse(	at org.apache.xerces.parsers.XMLParser.parse(	at org.apache.xerces.parsers.AbstractSAXParser.parse(	at javax.xml.parsers.SAXParser.parse(Unknown Source)	at org.apache.openjpa.lib.meta.XMLMetaDataParser.parseNewResource(	at org.apache.openjpa.lib.meta.XMLMetaDataParser.parse(	at org.apache.openjpa.lib.meta.XMLMetaDataParser.parse(	at org.apache.openjpa.meta.AbstractCFMetaDataFactory.parse(