java.lang.NumberFormatException: For input string: "0x20000"

GitHub | micrk | 5 months ago
  1. 0

    NumberFormatException: For input string: "0x20000"

    GitHub | 5 months ago | micrk
    java.lang.NumberFormatException: For input string: "0x20000"
  2. 0

    apk-parser 需要更新

    GitHub | 2 months ago | junyuecao
    java.lang.NumberFormatException: For input string: "0x20000"
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    NumberFormatException: For input string: "0x20000"

    GitHub | 2 months ago | shizhy1986
    java.lang.NumberFormatException: For input string: "0x20000"
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    AndroidMainfest解析错误

    GitHub | 2 months ago | yanunon
    java.lang.NumberFormatException: For input string: "0x20000"
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    Stack Overflow | 1 year ago | We are Borg
    java.lang.NumberFormatException: For input string: "null"

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Root Cause Analysis

  1. java.lang.NumberFormatException

    For input string: "0x20000"

    at java.lang.NumberFormatException.forInputString()
  2. Java RT
    Integer.valueOf
    1. java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
    2. java.lang.Integer.parseInt(Integer.java:580)
    3. java.lang.Integer.valueOf(Integer.java:766)
    3 frames
  3. net.dongliu.apk
    AbstractApkParser.parseApkMeta
    1. net.dongliu.apk.parser.struct.xml.Attributes.getInt(Attributes.java:40)
    2. net.dongliu.apk.parser.parser.ApkMetaTranslator.onStartTag(ApkMetaTranslator.java:56)
    3. net.dongliu.apk.parser.parser.CompositeXmlStreamer.onStartTag(CompositeXmlStreamer.java:19)
    4. net.dongliu.apk.parser.parser.BinaryXmlParser.readXmlNodeStartTag(BinaryXmlParser.java:189)
    5. net.dongliu.apk.parser.parser.BinaryXmlParser.parse(BinaryXmlParser.java:101)
    6. net.dongliu.apk.parser.AbstractApkParser.transBinaryXml(AbstractApkParser.java:164)
    7. net.dongliu.apk.parser.AbstractApkParser.parseManifestXml(AbstractApkParser.java:123)
    8. net.dongliu.apk.parser.AbstractApkParser.parseApkMeta(AbstractApkParser.java:105)
    8 frames