java.lang.IllegalArgumentException: Minimum abbreviation width is 4

Atlassian JIRA | Taiwo Akindele [Atlassian] | 9 months ago
  1. 0

    GitHub comment 1287#53389438

    GitHub | 2 years ago | bpindelski
    java.lang.IllegalArgumentException: (minimum <= value <= maximum) is false
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  3. 0

    Error trying to edit a dropped question

    GitHub | 2 years ago | hemberger
    java.lang.IllegalArgumentException: (minimum <= value <= maximum) is false
  4. 0

    Can't open locate duplicates parameters dialog

    YouTrack | 6 years ago
    java.lang.IllegalArgumentException: (minimum <= value <= maximum) is false

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    Root Cause Analysis

    1. java.lang.IllegalArgumentException

      Minimum abbreviation width is 4

      at org.apache.commons.lang.StringUtils.abbreviate()
    2. Commons Lang
      StringUtils.abbreviate
      1. org.apache.commons.lang.StringUtils.abbreviate(StringUtils.java:5920)[commons-lang-2.6.jar:2.6]
      1 frame