java.lang.NumberFormatException: For input string: "0-b22" at java.lang.NumberFormatException.forInputString(Unk nown Source)

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Root Cause Analysis

  1. java.lang.NumberFormatException

    For input string: "0-b22" at java.lang.NumberFormatException.forInputString(Unk nown Source)

    at java.lang.Integer.parseInt()
  2. Java RT
    Integer.<init>
    1. java.lang.Integer.parseInt(Unknown Source)
    2. java.lang.Integer.<init>(Unknown Source)
    2 frames