java.lang.NumberFormatException: For input string: "11111111111111111111111111111111"

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  1. ,

    You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.

  2. ,

    Can occur when you try to convert a String to a numeric value but the String is not well formatted for the conversion.

Solutions on the web

via Coderanch by Campbell Ritchie, 1 year ago
For input string: "11111111111111111111111111111111"
via Stack Overflow by jcm
, 2 years ago
For input string: "11111111111111111111111111111111"
via Coderanch by bue curt, 1 year ago
For input string: ""
via GitHub by arjunnair1989
, 1 year ago
For input string: " 1"
via Stack Overflow by Jasmine.Olivra
, 2 years ago
For input string: ""
via Stack Overflow by user2127482
, 2 years ago
For input string: "XCoord"
java.lang.NumberFormatException: For input string: "11111111111111111111111111111111"	at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)	at java.lang.Integer.parseInt(Integer.java:461)	at IntegerParseDemo.main(IntegerParseDemo.java:5)