java.lang.NumberFormatException: For input string: "11111111111111111111111111111111"

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You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.

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Solutions on the web

via Coderanch by Campbell Ritchie, 1 year ago
For input string: "11111111111111111111111111111111"
via Stack Overflow by jcm
, 1 year ago
For input string: "11111111111111111111111111111111"
via Coderanch by bue curt, 1 year ago
java.lang.NumberFormatException: For input string: "11111111111111111111111111111111"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
at java.lang.Integer.parseInt(Integer.java:461)
at undefined.IntegerParseDemo.main(IntegerParseDemo.java:5)

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