java.lang.NumberFormatException: For input string: ""0"

GitHub | MarkRx | 7 months ago
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Root Cause Analysis

  1. java.lang.NumberFormatException

    For input string: ""0"

    at java.lang.NumberFormatException.forInputString()
  2. Java RT
    Integer.valueOf
    1. java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
    2. java.lang.Integer.parseInt(Integer.java:569)
    3. java.lang.Integer.valueOf(Integer.java:766)
    3 frames
  3. Spring Context
    CronSequenceGenerator.getRange
    1. org.springframework.scheduling.support.CronSequenceGenerator.getRange(CronSequenceGenerator.java:363)
    1 frame