java.lang.NumberFormatException: For input string: ".2201215E"

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via Stack Overflow by Craigy
, 2 years ago
For input string: ".200172E4.200172"
via Stack Overflow by Ganesh
, 2 years ago
via Stack Overflow by peterh
, 1 year ago
For input string: "880044E.3880044E3"
via udojava.com by Unknown author, 1 year ago
java.lang.NumberFormatException: For input string: ".2201215E"
at sun.misc.FloatingDecimal.readJavaFormatString(FloatingDecimal.java:1222)
at java.lang.Double.parseDouble(Double.java:510)
at java.text.DigitList.getDouble(DigitList.java:151)
at java.text.DecimalFormat.parse(DecimalFormat.java:1303)
at java.text.SimpleDateFormat.subParse(SimpleDateFormat.java:1591)
at java.text.SimpleDateFormat.parse(SimpleDateFormat.java:1312)
at java.text.DateFormat.parse(DateFormat.java:335)
at com.icesoft.faces.webapp.CompatResourceServlet.service(CompatResourceServlet.java:60)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:717)

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