java.lang.NumberFormatException: For input string: "E152"

Coderanch | mitesh vyas | 9 years ago
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    Root Cause Analysis

    1. java.lang.NumberFormatException

      For input string: "E152"

      at java.lang.NumberFormatException.forInputString()
    2. Java RT
      DateFormat.parse
      1. java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
      2. java.lang.Long.parseLong(Long.java:394)
      3. java.lang.Long.parseLong(Long.java:452)
      4. java.text.DigitList.getLong(DigitList.java:149)
      5. java.text.DecimalFormat.parse(DecimalFormat.java:1068)
      6. java.text.SimpleDateFormat.subParse(SimpleDateFormat.java:1705)
      7. java.text.SimpleDateFormat.parse(SimpleDateFormat.java:1156)
      8. java.text.DateFormat.parse(DateFormat.java:333)
      8 frames