java.lang.NumberFormatException: For input string: "3 "

Searched on Google with the first line of a JAVA stack trace?

We can recommend more relevant solutions and speed up debugging when you paste your entire stack trace with the exception message. Try a sample exception.

Recommended solutions based on your search

Samebug tips

,

You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.

,

Java does not handle IPv6 nameservers before 1.8.0_60. Upgrade to the latest JVM.

Solutions on the web

via Oracle Community by 807569, 1 year ago
via Coderanch by Mark Hughes, 1 year ago
For input string: "3 "
via GitHub by yoav-zibin
, 1 year ago
For input string: "3249660004697307829"
via Google Groups by Puja Gupta, 5 months ago
For input string: "--conf"
java.lang.NumberFormatException: For input string: "3 "
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)

Users with the same issue

Samebug visitor profile picture
Unknown user
Once, 5 months ago
Samebug visitor profile picture
Unknown user
Once, 1 year ago
Samebug visitor profile picture
Unknown user
Once, 1 year ago
Samebug visitor profile picture
Unknown user
Once, 1 year ago
Samebug visitor profile picture
Unknown user
Once, 1 year ago
264 more bugmates

Know the solutions? Share your knowledge to help other developers to debug faster.