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    You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.

Solutions on the web

via Oracle Community by 807555, 1 year ago
via apache.org by Unknown author, 2 years ago
For input string: "8119844 1 4472499 > 2013-01-29 00:00:00.0 1 4 1 \N \N \N \N \N \N \N \N \N \N 8 \N \N \N \N \N > 1 \N \N 3 2 \N 1" at > java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
via Coderanch by sowjan kumar, 1 year ago
via Coderanch by sowjan kumar, 1 year ago
java.lang.NumberFormatException: n at java.lang.Integer.parseInt(Integer.java:414) at java.lang.Integer.parseInt(Integer.java:463) at MyInput.readInt(MyInput.java:27) at SalaryComputation3.getJobClass(SalaryComputation3.java:85) at SalaryComputation3.main(SalaryComputation3.java:61)