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    You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.

Solutions on the web

via Oracle Community by 807555, 1 year ago
via by Unknown author, 2 years ago
For input string: "8119844 1 4472499 > 2013-01-29 00:00:00.0 1 4 1 \N \N \N \N \N \N \N \N \N \N 8 \N \N \N \N \N > 1 \N \N 3 2 \N 1" at > java.lang.NumberFormatException.forInputString(
via Coderanch by sowjan kumar, 1 year ago
via Coderanch by sowjan kumar, 1 year ago
java.lang.NumberFormatException: n at java.lang.Integer.parseInt( at java.lang.Integer.parseInt( at MyInput.readInt( at SalaryComputation3.getJobClass( at SalaryComputation3.main(