java.lang.NumberFormatException

For input string: "0.0000000000null"

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Solutions on the web5368

  • via Coderanch by Elinor Chang, 7 months ago
    For input string: "0.0000000000null"
  • via Coderanch by Elinor Chang, 11 months ago
    For input string: "0.0000000000null"
  • via Stack Overflow by Shantanu
    , 1 year ago
    For input string: "string"
  • Stack trace

    • java.lang.NumberFormatException: For input string: "0.0000000000null" at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48) at java.lang.FloatingDecimal.readJavaFormatString(FloatingDecimal.java:1207) at java.lang.Double.valueOf(Double.java:202) at java.math.BigDecimal.doubleValue(BigDecimal.java:1033)

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