java.lang.IllegalArgumentException: thresholdName must be one of these values: SUCCESS,UNSTABLE,FAILURE

Jenkins JIRA | gangadhar chalapaka | 1 year ago
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Root Cause Analysis

  1. java.lang.IllegalArgumentException

    thresholdName must be one of these values: SUCCESS,UNSTABLE,FAILURE

    at com.google.common.base.Preconditions.checkArgument()
  2. Guava
    Preconditions$checkArgument.call
    1. com.google.common.base.Preconditions.checkArgument(Preconditions.java:88)
    2. com.google.common.base.Preconditions$checkArgument.call(Unknown Source)
    2 frames
  3. javaposse.jobdsl.dsl
    DownstreamTriggerContext.blockingThreshold
    1. javaposse.jobdsl.dsl.helpers.common.DownstreamTriggerContext.blockingThreshold(DownstreamTriggerContext.groovy:111)
    1 frame