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Solutions on the web

via Coderanch by Richard Johnson, 1 year ago
For input string: "a6acda419199c58a"
via Stack Overflow by aF.
, 2 years ago
For input string: ""
via Stack Overflow by aurelius
, 11 months ago
via Stack Overflow by Hooman
, 2 years ago
For input string: "userName"
via Stack Overflow by Cjen1
, 1 year ago
java.lang.NumberFormatException: For input string: "a6acda419199c58a" at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48) at java.lang.Long.parseLong(Long.java:406)