org.hibernate.exception.SQLGrammarException: could not insert: [hello.Message]

hibernate.org | 9 months ago
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    hibernate.org | 9 months ago
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    Root Cause Analysis

    1. java.sql.SQLException

      Table not found in statement [/* insert hello.Message */ insert into MESSAGES (MESSAGE_ID, MESSAGE_TEXT, NEXT_MESSAGE_ID) values (null, ?, ?)]

      at org.hsqldb.jdbc.Util.throwError()
    2. HSQLDB
      jdbcConnection.prepareStatement
      1. org.hsqldb.jdbc.Util.throwError(Unknown Source)
      2. org.hsqldb.jdbc.jdbcPreparedStatement.<init>(Unknown Source)
      3. org.hsqldb.jdbc.jdbcConnection.prepareStatement(Unknown Source)
      3 frames
    3. Java RT
      Method.invoke
      1. sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
      2. sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
      3. sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
      4. java.lang.reflect.Method.invoke(Unknown Source)
      4 frames
    4. c3p0:JDBC DataSources/Resource Pools
      ThreadPoolAsynchronousRunner$PoolThread.run
      1. com.mchange.v2.c3p0.stmt.GooGooStatementCache$3.run(GooGooStatementCache.java:445)
      2. com.mchange.v2.async.ThreadPoolAsynchronousRunner$PoolThread.run(ThreadPoolAsynchronousRunner.java:368)
      2 frames