java.lang.NumberFormatException: For input string: "2200000000"

Oracle Community | user591174-Oracle | 1 year ago
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Root Cause Analysis

  1. java.lang.NumberFormatException

    For input string: "2200000000"

    at java.lang.NumberFormatException.forInputString()
  2. Java RT
    Integer.parseInt
    1. java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
    2. java.lang.Integer.parseInt(Integer.java:461)
    3. java.lang.Integer.parseInt(Integer.java:499)
    3 frames