java.lang.NumberFormatException

For input string: " 36"

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Solutions on the web5372

  • via Coderanch by jonas okwara, 11 months ago
    For input string: " 36"
  • via Oracle Community by 450969, 1 year ago
    For input string: "ago 22, 2005 18:20:36"
  • via Jenkins JIRA by uwodi, 11 months ago
    For input string: "1970-01-16T21:55:36-0500 -0500"
  • Stack trace

    • java.lang.NumberFormatException: For input string: " 36" at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48) at java.lang.Integer.parseInt(Integer.java:447) at java.lang.Integer.parseInt(Integer.java:497) at P_package.DialogInterFace.addRecordActionEvent(DialogInterFace.java:160) at P_package.DialogInterFace$1.actionPerformed(DialogInterFace.java:93) at javax.swing.AbstractButton.fireActionPerformed(AbstractButton.java:1995)

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