java.lang.NumberFormatException: For input string: " 36"

Coderanch | jonas okwara | 9 years ago
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    Coderanch | 9 years ago | jonas okwara
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Root Cause Analysis

  1. java.lang.NumberFormatException

    For input string: " 36"

    at java.lang.NumberFormatException.forInputString()
  2. Java RT
    Integer.parseInt
    1. java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
    2. java.lang.Integer.parseInt(Integer.java:447)
    3. java.lang.Integer.parseInt(Integer.java:497)
    3 frames
  3. P_package
    DialogInterFace$1.actionPerformed
    1. P_package.DialogInterFace.addRecordActionEvent(DialogInterFace.java:160)
    2. P_package.DialogInterFace$1.actionPerformed(DialogInterFace.java:93)
    2 frames
  4. Java RT
    AbstractButton.fireActionPerformed
    1. javax.swing.AbstractButton.fireActionPerformed(AbstractButton.java:1995)
    1 frame