java.lang.NumberFormatException: For input string: " 4"

Searched on Google with the first line of a JAVA stack trace?

We can recommend more relevant solutions and speed up debugging when you paste your entire stack trace with the exception message. Try a sample exception.

Recommended solutions based on your search

Samebug tips

,

You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.

,

Can occur when you try to convert a String to a numeric value but the String is not well formatted for the conversion.

Solutions on the web

via Stack Overflow by HotShot51015
, 1 year ago
via Eclipse Bugzilla by sbalusani, 1 year ago
via Eclipse Bugzilla by dj.houghton, 1 year ago
via ws-users by mith86, 1 year ago
For input string: "Client"
via ws-users by mith86, 1 year ago
For input string: "Client"
java.lang.NumberFormatException: For input string: " 4"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:569)
at java.lang.Integer.parseInt(Integer.java:615)
at undefined.BlogEntryTester.main(BlogEntryTester.java:59)

Users with the same issue

Once, 1 hour ago
4 times, 6 days ago
16 times, 1 week ago
6 times, 1 week ago
30 times, 1 week ago

Write tip

Know the solutions? Share your knowledge to help other developers to debug faster.