javax.persistence.PersistenceException

org.hibernate.exception.SQLGrammarException: could not get next sequence value

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Solutions on the web1418

  • via hibernate.org by Unknown author, 1 year ago
    org.hibernate.exception.SQLGrammarException: could not get next sequence value
  • via openxava by tokugawa69
    , 11 months ago
    org.hibernate.exception.SQLGrammarException: could not get next sequence value
  • org.hibernate.exception.SQLGrammarException: could not get next sequence value
  • Stack trace

    • javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not get next sequence value at org.hibernate.ejb.AbstractEntityManagerImpl.throwPersistenceException(AbstractEntityManagerImpl.java:614) at org.hibernate.ejb.AbstractEntityManagerImpl.persist(AbstractEntityManagerImpl.java:226) at org.openxava.model.impl.JPAPersistenceProvider.persist(JPAPersistenceProvider.java:35) at org.openxava.model.impl.POJOPersistenceProviderBase.create(POJOPersistenceProviderBase.java:148) at org.openxava.model.impl.MapFacadeBean.create(MapFacadeBean.java:723) at org.openxava.model.impl.MapFacadeBean.create(MapFacadeBean.java:41) at org.openxava.model.MapFacade.create(MapFacade.java:110) at org.openxava.actions.SaveAction.execute(SaveAction.java:27) at org.openxava.controller.ModuleManager.executeAction(ModuleManager.java:329) at org.openxava.controller.ModuleManager.executeAction(ModuleManager.java:254) at org.openxava.controller.ModuleManager.execute(ModuleManager.java:220)

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    Users with the same issue

    Unknown user
    Once, 1 year ago
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    Unknown user
    Once, 11 months ago
    Unknown user
    Once, 1 year ago
    Unknown user
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    3 more bugmates