org.hibernate.exception.SQLGrammarException: could not get next sequence value

openxava | daviles | 8 years ago
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    openxava | 8 years ago | daviles
    org.hibernate.exception.SQLGrammarException: could not get next sequence value

    Root Cause Analysis

    1. org.hibernate.exception.SQLGrammarException

      could not get next sequence value

      at org.openxava.model.impl.POJOPersistenceProviderBase.create()
    2. org.openxava.model
      MapFacade.create
      1. org.openxava.model.impl.POJOPersistenceProviderBase.create(POJOPersistenceProviderBase.java:153)
      2. org.openxava.model.impl.MapFacadeBean.create(MapFacadeBean.java:723)
      3. org.openxava.model.impl.MapFacadeBean.create(MapFacadeBean.java:41)
      4. org.openxava.model.MapFacade.create(MapFacade.java:110)
      4 frames
    3. org.openxava.actions
      SaveAction.execute
      1. org.openxava.actions.SaveAction.execute(SaveAction.java:27)
      1 frame
    4. org.openxava.controller
      ModuleManager.execute
      1. org.openxava.controller.ModuleManager.executeAction(ModuleManager.java:326)
      2. org.openxava.controller.ModuleManager.executeAction(ModuleManager.java:252)
      3. org.openxava.controller.ModuleManager.execute(ModuleManager.java:218)
      3 frames