java.lang.NumberFormatException: For input string: "10000000000"

GitHub | madrob | 7 months ago
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Root Cause Analysis

  1. java.lang.NumberFormatException

    For input string: "10000000000"

    at java.lang.NumberFormatException.forInputString()
  2. Java RT
    Integer.parseInt
    1. java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
    2. java.lang.Integer.parseInt(Integer.java:495)
    3. java.lang.Integer.parseInt(Integer.java:527)
    3 frames
  3. com.yahoo.ycsb
    Client.main
    1. com.yahoo.ycsb.workloads.CoreWorkload.init(CoreWorkload.java:399)
    2. com.yahoo.ycsb.Client.main(Client.java:1016)
    2 frames