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    The json is invalid or you try to map to a different model.

Solutions on the web

via GitHub by obilodeau
, 1 year ago
End of input at character 0 of
via GitHub by obilodeau
, 1 year ago
End of input at character 0 of
via Stack Overflow by ABeReal
, 10 months ago
via GitHub by dvdbrk
, 7 months ago
End of input at character 0 of
via Stack Overflow by R.H
, 5 months ago
End of input at character 0 of
via Stack Overflow by Unknown author, 2 years ago
End of input at character 1 of
org.json.JSONException: End of input at character 0 of	at org.json.JSONTokener.syntaxError(JSONTokener.java:450)	at org.json.JSONTokener.nextValue(JSONTokener.java:97)	at org.json.JSONObject.(JSONObject.java:156)	at org.json.JSONObject.(JSONObject.java:173)	at org.tomdroid.sync.web.OAuthConnection.getAuthorizationUrl(OAuthConnection.java:136)	at org.tomdroid.sync.web.SnowySyncService$1.run(SnowySyncService.java:102)	at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1112)	at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:587)	at java.lang.Thread.run(Thread.java:818)