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  1. ,

    The json is invalid or you try to map to a different model.

Solutions on the web

via GitHub by obilodeau
, 1 year ago
End of input at character 0 of
via Stack Overflow by ABeReal
, 1 year ago
via GitHub by dvdbrk
, 11 months ago
End of input at character 0 of
via Stack Overflow by R.H
, 8 months ago
End of input at character 0 of
via GitHub by bastei
, 1 year ago
End of input at character 0 of
via Stack Overflow by Unknown author, 2 years ago
End of input at character 1 of
org.json.JSONException: End of input at character 0 of 	at org.json.JSONTokener.syntaxError(JSONTokener.java:446)	at org.json.JSONTokener.nextValue(JSONTokener.java:93)	at org.json.JSONObject.(JSONObject.java:154)	at org.json.JSONObject.(JSONObject.java:171)	at org.tomdroid.sync.web.SnowySyncService$3.run(SnowySyncService.java:155)	at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1068)	at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:561)	at java.lang.Thread.run(Thread.java:1102)