java.lang.IllegalStateException

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  • $? returns errorlevel 0 instead of 4
    via Unix & Linux by daZza
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    • java.lang.IllegalStateException: EJBCLIENT000025: No EJB receiver available for handling [appName:xxx, moduleName:xxx-ejb-generic, distinctName:] combination for invocation context org.xxx.EJBClientInvocationContext@50a638b5 at org.xxx.EJBClientContext.requireEJBReceiver(EJBClientContext.java:727) at org.xxx.ReceiverInterceptor.handleInvocation(ReceiverInterceptor.java:116) at org.xxx.EJBClientInvocationContext.sendRequest(EJBClientInvocationContext.java:183) at org.xxx.sendRequestWithPossibleRetries(EJBInvocationHandler.java:253) at org.xxx.doInvoke(EJBInvocationHandler.java:198) at org.xxx.doInvoke(EJBInvocationHandler.java:181) at org.xxx.invoke(EJBInvocationHandler.java:144) at com.sun.proxy.$Proxy2.evalWorkflowStatus(Unknown Source) at xxx.ejb.workflow.test.ClientAsyncComStrategy.startWorkflow(ClientAsyncComStrategy.java:83) at xxx.ejb.workflow.test.yyy.startWorkflow(yyy.java:219) at xxx.ejb.workflow.test.yyy.main(yyy.java:132)
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