java.lang.NumberFormatException: For input string: "1"

Searched on Google with the first line of a JAVA stack trace?

We can recommend more relevant solutions and speed up debugging when you paste your entire stack trace with the exception message. Try a sample exception.

Recommended solutions based on your search

Samebug tips

,

You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.

,

Java does not handle IPv6 nameservers before 1.8.0_60. Upgrade to the latest JVM.

java.lang.NumberFormatException: For input string: "1"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:580)
at java.lang.Integer.parseInt(Integer.java:615)
at movieranker.MovieRanker.createData(MovieRanker.java:45)
at movieranker.MovieRanker.main(MovieRanker.java:25)

Users with the same issue

Samebug visitor profile picture
Unknown user
Once, 2 years ago
2 times, 1 year ago
2 times, 2 weeks ago
2 times, 5 months ago
8 times, 9 months ago

Write tip

Know the solutions? Share your knowledge to help other developers to debug faster.