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via Stack Overflow by Deepa
, 1 year ago
Exception while streaming tweets 404:The URI requested is invalid or the resource requested, such as a user, does not exist. Unknown URL. See Twitter Streaming API documentation at htp://dev.twitter.com/pages/streaming_api Relevant discussions can
via Stack Overflow by Robin
, 1 year ago
Exception while streaming tweets stream.twitter.com Relevant discussions can be found on the Internet at: http://www.google.co.jp/search?q=d0031b0b or http://www.google.co.jp/search?q=1db75522 TwitterException{exceptionCode=[d0031b0b-1db75522 db667dea-99334ae4], statusCode=-1, message=null, code=-1, retryAfter=-1, rateLimitStatus=null, version=3.0.3}
via Stack Overflow by Mohit.kc
, 2 months ago
Exception while streaming tweets Received fatal alert: access_denied** Relevant discussions can be found on the Internet at: http://www.google.co.jp/search?q=d0031b0b or http://www.google.co.jp/search?q=1db75522 TwitterException
twitter.TwitterSource: Exception while streaming tweets
404:The URI requested is invalid or the resource requested, such as a user, does not exist.
Unknown URL. See Twitter Streaming API documentation at htp://dev.twitter.com/pages/streaming_api
Relevant discussions can be found on the Internet at:
    htp://www.google.co.jp/search?q=ec814753 or
    htp://www.google.co.jp/search?q=0a74cca1
TwitterException{exceptionCode=[ec814753-0a74cca1], statusCode=404, retryAfter=-1, rateLimitStatus=null, featureSpecificRateLimitStatus=null, version=2.2.6}	at twitter4j.internal.http.HttpClientImpl.request(HttpClientImpl.java:185)	at twitter4j.internal.http.HttpClientWrapper.request(HttpClientWrapper.java:65)	at twitter4j.internal.http.HttpClientWrapper.get(HttpClientWrapper.java:93)	at twitter4j.TwitterStreamImpl.getSampleStream(TwitterStreamImpl.java:160)	at twitter4j.TwitterStreamImpl$4.getStream(TwitterStreamImpl.java:149)	at twitter4j.TwitterStreamImpl$4.getStream(TwitterStreamImpl.java:147)	at twitter4j.TwitterStreamImpl$TwitterStreamConsumer.run(TwitterStreamImpl.java:426)