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Samebug tips

  1. ,

    You are trying to deserialize a type for which Jackson does not provide a default mapper. You should create your custom mapper for this type.

  2. ,

    The easiest solution is to provide a default constructor for the class you want to convert from/to json.

Solutions on the web

via Stack Overflow by daydreamer
, 1 year ago
Unexpected token (END_OBJECT), expected FIELD_NAME: missing property '@type' that is to contain type id (for class com.datasources.DataSource) at [Source: /var/folders/g3/wtbqfj7d5fsbkz1gm74kqy380000gn/T/junit5577276768876379004/fileDataSource.json
via GitHub by quilicicf
, 1 year ago
Unexpected token (END_OBJECT), expected FIELD_NAME: missing property 'type' that is to contain type id (for class com.fasterxml.jackson.module.jsonSchema.JsonSchema) at [Source: {}; line: 1, column: 2]
via GitHub by rpatrick00
, 2 years ago
Unexpected token (FIELD_NAME), expected START_OBJECT: need JSON Object to contain As.WRAPPER_OBJECT type information for class test.Computer at [Source: company-jackson.xml; line: 4, column: 9] (through reference chain: test.Company["computers"]->ja
via Tridion by Gulshan Thakur
, 1 year ago
Unexpected token (END_OBJECT), expected FIELD_NAME: missing property 'FieldType' that is to contain type id (for class org.dd4t.contentmodel.impl.BaseField) at [Source: {"Folder":{"PublicationId":"tcm:0-301-1","Id":"tcm:301-3014-2","Title":"Tes
via GitHub by ecdavis
, 1 year ago
Can not deserialize instance of java.lang.String out of START_ARRAY token at [Source: [B@460ebd80; line: 1, column: 17] (through reference chain: com.amazonaws.services.lambda.invoke.LambdaFunctionError["stackTrace"]->java.util.ArrayList[0])
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