javax.xml.soap.SOAPException: Fault code QName '2104' must be namespace qualified!

Stack Overflow | Abhilash | 8 months ago
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Root Cause Analysis

  1. javax.xml.soap.SOAPException

    Fault code QName '2104' must be namespace qualified!

    at oracle.j2ee.ws.saaj.soap.soap11.Fault11.setFaultCode()
  2. oracle.j2ee.ws
    SOAPFactoryImpl.createFault
    1. oracle.j2ee.ws.saaj.soap.soap11.Fault11.setFaultCode(Fault11.java:334)
    2. oracle.j2ee.ws.saaj.soap.soap11.SOAPFactory11.createFault(SOAPFactory11.java:51)
    3. oracle.j2ee.ws.saaj.soap.SOAPFactoryImpl.createFault(SOAPFactoryImpl.java:117)
    3 frames
  3. JAX-WS RI Runtime Bundle
    SEIStub.invoke
    1. com.sun.xml.ws.fault.SOAP11Fault.getProtocolException(SOAP11Fault.java:184)
    2. com.sun.xml.ws.fault.SOAPFaultBuilder.createException(SOAPFaultBuilder.java:128)
    3. com.sun.xml.ws.client.sei.StubHandler.readResponse(StubHandler.java:253)
    4. com.sun.xml.ws.db.DatabindingImpl.deserializeResponse(DatabindingImpl.java:205)
    5. com.sun.xml.ws.db.DatabindingImpl.deserializeResponse(DatabindingImpl.java:292)
    6. com.sun.xml.ws.client.sei.SyncMethodHandler.invoke(SyncMethodHandler.java:119)
    7. com.sun.xml.ws.client.sei.SyncMethodHandler.invoke(SyncMethodHandler.java:92)
    8. com.sun.xml.ws.client.sei.SEIStub.invoke(SEIStub.java:161)
    8 frames