java.lang.IllegalArgumentException: Address of hyperlink must be a valid URI

Stack Overflow | VenkiArun | 3 months ago
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    java.lang.IllegalArgumentException: Address of hyperlink must be a valid URI
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Root Cause Analysis

  1. java.net.URISyntaxException

    Illegal character in path at index 27: /home/user/Desktop/class Name/ExcelApp/ '/home/user/Desktop/pathfile/Employee Details /1.pdf'

    at java.net.URI$Parser.fail()
  2. Java RT
    URI.<init>
    1. java.net.URI$Parser.fail(URI.java:2810)
    2. java.net.URI$Parser.checkChars(URI.java:2983)
    3. java.net.URI$Parser.parseHierarchical(URI.java:3067)
    4. java.net.URI$Parser.parse(URI.java:3025)
    5. java.net.URI.<init>(URI.java:577)
    5 frames
  3. Apache POI
    XSSFHyperlink.validate
    1. org.apache.poi.xssf.usermodel.XSSFHyperlink.validate(XSSFHyperlink.java:210)
    1 frame