java.lang.NumberFormatException

For input string: "20A0600000000000L"

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Solutions on the web3579

  • via GitHub by smalljason
    ,
  • via by Kristine O'Connor,
  • Stack trace

    • java.lang.NumberFormatException: For input string: "20A0600000000000L" at java.lang.NumberFormatException.forInputString(Unknown Source) at java.lang.Long.parseLong(Unknown Source) at java.lang.Long.valueOf(Unknown Source) at java.lang.Long.decode(Unknown Source)

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