java.lang.NumberFormatException: For input string: "20A0600000000000L"

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Solutions on the web

via GitHub by evless
, 2 months ago
For input string: ""
via Bugzilla by gilda, 1 year ago
java.lang.NumberFormatException: For input string: "20A0600000000000L"
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Long.parseLong(Unknown Source)
at java.lang.Long.valueOf(Unknown Source)
at java.lang.Long.decode(Unknown Source)

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