Searched on Google with the first line of a JAVA stack trace?

We can recommend more relevant solutions and speed up debugging when you paste your entire stack trace with the exception message. Try a sample exception.

Recommended solutions based on your search

Samebug tips

  1. ,

    You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.

  2. ,

    Can occur when you try to convert a String to a numeric value but the String is not well formatted for the conversion.

Solutions on the web

via Oracle Community by 807549, 1 year ago
For input string: "1 .0"
via Stack Overflow by JJ Thomson
, 1 year ago
via by Unknown author, 1 year ago
via Stack Overflow by gpthree
, 2 years ago
via Stack Overflow by BornForJava
, 2 years ago
java.lang.NumberFormatException: For input string: "1
.0"	at java.lang.NumberFormatException.forInputString(	at java.lang.Integer.parseInt(	at java.lang.Integer.parseInt(	at Chart.main(