Searched on Google with the first line of a JAVA stack trace?

We can recommend more relevant solutions and speed up debugging when you paste your entire stack trace with the exception message. Try a sample exception.

Recommended solutions based on your search

Samebug tips

  1. ,
    via vogella.com by Unknown author

    Any worker thread runs in background, since it is not intended to loop, is not connected to a Looper.for example doInBackground(). its implementation returns will be passed to onPostExecute() which runs on the UI thread.

Solutions on the web

via Stack Overflow by user1851366
, 1 year ago
Can't create handler inside thread that has not called Looper.prepare()
via Stack Overflow by noon hijazi
, 4 months ago
Can't create handler inside thread that has not called Looper.prepare()
via GitHub by ghost
, 1 year ago
Can't create handler inside thread that has not called Looper.prepare()
via Stack Overflow by Sharmila Shankar
, 1 year ago
via GitHub by drojokef
, 1 year ago
Can't create handler inside thread that has not called Looper.prepare()
java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare() at android.os.Handler.<init>(Handler.java:200) at android.os.Handler.<init>(Handler.java:114) at android.app.Dialog.<init>(Dialog.java:119) at android.app.Dialog.<init>(Dialog.java:168) at android.support.v7.app.AppCompatDialog.<init>(AppCompatDialog.java:43) at android.support.v7.app.AlertDialog.<init>(AlertDialog.java:95) at android.support.v7.app.AlertDialog$Builder.create(AlertDialog.java:927) at android.support.v7.app.AlertDialog$Builder.show(AlertDialog.java:952)