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  1. ,
    via GitHub by h6ah4i

    You have to provide valid identical number for each child items.

Solutions on the web

via GitHub by lololiu
, 1 year ago
Inconsistency detected. Invalid item position 20(offset:20).state:21
via GitHub by yanxinmiao
, 6 months ago
via sourceforge.net by Unknown author, 1 year ago
Inconsistency detected. Invalid item position {NUMBER1}(offset:-1).state:{NUMBER2(>NUMBER1)}
via Stack Overflow by wisemann
, 2 years ago
via GitHub by zpfang9008
, 1 year ago
Inconsistency detected. Invalid item position 21(offset:21).state:22
via GitHub by blFeedbackBot
, 2 years ago
Inconsistency detected. Invalid item position 21(offset:21).state:59
java.lang.IndexOutOfBoundsException: Inconsistency detected. Invalid item position  20(offset:20).state:21	at android.support.v7.widget.RecyclerView$Recycler.getViewForPosition(RecyclerView.java:4659)	at android.support.v7.widget.RecyclerView$Recycler.getViewForPosition(RecyclerView.java:4617)	at android.support.v7.widget.LinearLayoutManager$LayoutState.next(LinearLayoutManager.java:1994)	at android.support.v7.widget.LinearLayoutManager.layoutChunk(LinearLayoutManager.java:1390)	at android.support.v7.widget.LinearLayoutManager.fill(LinearLayoutManager.java:1353)	at android.support.v7.widget.LinearLayoutManager.scrollBy(LinearLayoutManager.java:1180)	at android.support.v7.widget.LinearLayoutManager.scrollVerticallyBy(LinearLayoutManager.java:1031)	at android.support.v7.widget.RecyclerView.scrollByInternal(RecyclerView.java:1529)	at android.support.v7.widget.RecyclerView.onTouchEvent(RecyclerView.java:2486)