java.lang.IllegalArgumentException: Health-URL is not valid

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Solutions on the web

via GitHub by pradeepkusingh
, 1 year ago
Health-URL is not valid
via Stack Overflow by Prithvi Singh Rathore
, 2 years ago
url must start with '/' or with 'http(s)'
via Stack Overflow by Jaspreet Singh
, 2 years ago
Async support must be enabled on a servlet and for all filters involved in async request processing. This is done in Java code using the Servlet API or by adding "<async-supported>true</async-supported>" to servlet and filter declarations in web.xml. Also you must use a Servlet 3.0+ container
java.lang.IllegalArgumentException: Health-URL is not valid

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