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Samebug tips

  1. ,

    The easiest solution is to provide a default constructor for the class you want to convert from/to json.

  2. ,

    You are trying to deserialize a type for which Jackson does not provide a default mapper. You should create your custom mapper for this type.

Solutions on the web

via Stack Overflow by Qutbuddin Bohra
, 1 year ago
via Stack Overflow by Great Question
, 2 years ago
com.firebase.client.FirebaseException: Failed to bounce to type at com.firebase.client.DataSnapshot.getValue( at$1.onChildAdded( at com.firebase.client.core.ChildEventRegistration.fireEvent( at at com.firebase.client.core.view.EventRaiser$ at android.os.Handler.handleCallback( at android.os.Handler.dispatchMessage( at android.os.Looper.loop( at at java.lang.reflect.Method.invokeNative(Native Method) at java.lang.reflect.Method.invoke( at$ at at dalvik.system.NativeStart.main(Native Method)Caused by: com.fasterxml.jackson.databind.JsonMappingException: No suitable constructor found for type [simple type, class]: can not instantiate from JSON object (need to add/enable type information?) at [Source:; line: 1, column: 2] at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.deserializeFromObjectUsingNonDefault( at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserializeFromObject( at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize( at com.fasterxml.jackson.databind.ObjectMapper._readMapAndClose( at com.fasterxml.jackson.databind.ObjectMapper.readValue( at com.firebase.client.DataSnapshot.getValue( ... 13 more