java.lang.NumberFormatException: For input string: "0 111000000100100000001011000000000100000110000000001100000000000"

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Root Cause Analysis

  1. java.lang.NumberFormatException

    For input string: "0 111000000100100000001011000000000100000110000000001100000000000"

    at java.lang.NumberFormatException.forInputString()
  2. Java RT
    Integer.parseInt
    1. java.lang.NumberFormatException.forInputString(Unknown Source)
    2. java.lang.Integer.parseInt(Unknown Source)
    2 frames
  3. Unknown
    DecodeAudit.main
    1. DecodeAudit.main(DecodeHex.java:77)
    1 frame