java.lang.NumberFormatException: For input string: "/678"

Searched on Google with the first line of a JAVA stack trace?

We can recommend more relevant solutions and speed up debugging when you paste your entire stack trace with the exception message. Try a sample exception.

Recommended solutions based on your search

Samebug tips

  1. ,

    You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.

  2. ,

    Can occur when you try to convert a String to a numeric value but the String is not well formatted for the conversion.

Solutions on the web

via Stack Overflow by YaboyBenji
, 1 year ago
For input string: "/678"
via Eclipse Bugzilla by Darin_Swanson, 1 year ago
For input string: "osgi.bundles.defaultStartLevel"
via Google Groups by Longzhi Tan, 1 year ago
For input string: "X"
via Google Groups by adam, 2 years ago
For input string: "hello"
via Google Groups by moop™, 2 years ago
For input string: "5.0"
via Google Groups by Dionatan Hovoruski, 2 years ago
For input string: "nome"
java.lang.NumberFormatException: For input string: "/678"	at java.lang.NumberFormatException.forInputString(Unknown Source)	at java.lang.Integer.parseInt(Unknown Source)	at java.lang.Integer.parseInt(Unknown Source)	at DateChecker.main(DateChecker.java:42)