java.lang.StringIndexOutOfBoundsException: String index out of range: 98098

Coderanch | Pat Steele | 2 years ago
  1. 0

    A very basic code problem

    Coderanch | 2 years ago | Pat Steele
    java.lang.StringIndexOutOfBoundsException: String index out of range: 98098
  2. 0

    Specify Valid Characters in a String

    Oracle Community | 1 decade ago | 807599
    java.lang.StringIndexOutOfBoundsException: String index out of range:
  3. 0

    How to set print outputs equal to a variable in Java?

    Stack Overflow | 3 years ago | SJSharks
    java.lang.StringIndexOutOfBoundsException: String index out of range
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  5. 0

    Specify characters in a string

    Oracle Community | 1 decade ago | 807607
    java.lang.StringIndexOutOfBoundsException: String index out of range:
  6. 0

    2 java methods and a sorting algorithm - Java Programming - KnowCoding.com

    knowcoding.com | 11 months ago
    java.lang.StringIndexOutOfBoundsException: String index out of range: -1

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    Root Cause Analysis

    1. java.lang.StringIndexOutOfBoundsException

      String index out of range: 98098

      at java.lang.String.substring()
    2. Java RT
      Scanner.nextInt
      1. java.lang.String.substring(String.java:1950)
      2. java.util.Scanner.buildIntegerPatternString(Scanner.java:423)
      3. java.util.Scanner.integerPattern(Scanner.java:443)
      4. java.util.Scanner.nextInt(Scanner.java:2117)
      4 frames
    3. Unknown
      easydoesit.main
      1. easydoesit.main(easydoesit.java:16)
      1 frame