java.lang.StringIndexOutOfBoundsException: String index out of range: 1

Coderanch | Joseph Alrawi | 3 years ago
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  1. 0

    findWithinHorizon(".", 0).charAt(0); is really bugging me.

    Coderanch | 3 years ago | Joseph Alrawi
    java.lang.StringIndexOutOfBoundsException: String index out of range: 1
  2. 0
    samebug tip
    Thrown by String methods to indicate that an index is either negative or greater than the size of the string. For some methods such as the charAt method, this exception also is thrown when the index is equal to the size of the string.
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    Adding hyperlink to Excel while using Jexcelapi JAVA library

    Stack Overflow | 5 years ago | user1205275
    java.lang.StringIndexOutOfBoundsException: String index out of range: 1
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  5. 0

    IndexOutOfBoundsException, no clear cause

    Stack Overflow | 2 years ago
    java.lang.StringIndexOutOfBoundsException: String index out of range: 1
  6. 0

    Java lang stringindexoutofboundsexception string index out of range 1 - Java Programming - KnowCoding.com

    knowcoding.com | 1 year ago
    java.lang.StringIndexOutOfBoundsException: String index out of range: 1

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Root Cause Analysis

  1. java.lang.StringIndexOutOfBoundsException

    String index out of range: 1

    at java.lang.String.charAt()
  2. Java RT
    String.charAt
    1. java.lang.String.charAt(Unknown Source)
    1 frame
  3. Default
    Horizon.main
    1. Default.Horizon.main(Horizon.java:27)
    1 frame